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3754. Maximum Manhattan Distance After K Changes

Difficulty: Medium

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3754. Maximum Manhattan Distance After K Changes

Medium


You are given a string s consisting of the characters 'N', 'S', 'E', and 'W', where s[i] indicates movements in an infinite grid:

  • 'N' : Move north by 1 unit.
  • 'S' : Move south by 1 unit.
  • 'E' : Move east by 1 unit.
  • 'W' : Move west by 1 unit.

Initially, you are at the origin (0, 0). You can change at most k characters to any of the four directions.

Find the maximum Manhattan distance from the origin that can be achieved at any time while performing the movements in order.

The Manhattan Distance between two cells (xi, yi) and (xj, yj) is |xi - xj| + |yi - yj|.

 

Example 1:

Input: s = "NWSE", k = 1

Output: 3

Explanation:

Change s[2] from 'S' to 'N'. The string s becomes "NWNE".

Movement Position (x, y) Manhattan Distance Maximum
s[0] == 'N' (0, 1) 0 + 1 = 1 1
s[1] == 'W' (-1, 1) 1 + 1 = 2 2
s[2] == 'N' (-1, 2) 1 + 2 = 3 3
s[3] == 'E' (0, 2) 0 + 2 = 2 3

The maximum Manhattan distance from the origin that can be achieved is 3. Hence, 3 is the output.

Example 2:

Input: s = "NSWWEW", k = 3

Output: 6

Explanation:

Change s[1] from 'S' to 'N', and s[4] from 'E' to 'W'. The string s becomes "NNWWWW".

The maximum Manhattan distance from the origin that can be achieved is 6. Hence, 6 is the output.

 

Constraints:

  • 1 <= s.length <= 105
  • 0 <= k <= s.length
  • s consists of only 'N', 'S', 'E', and 'W'.

Solution

class Solution {
    public int maxDistance(String s, int k) {
        int ans = 0;
        char[][] dir = new char[][]{{'N', 'E'}, {'N', 'W'},{'S', 'E'},{'S', 'W'}};
        for (char[] d: dir) {
            for (int i = 0, curr = 0, t = k; i < s.length(); ++i){
                if (s.charAt(i) == d[0] || s.charAt(i) == d[1]){
                    if(t > 0 ) { t--; curr++; }
                    else 
                        curr--;
                }
                else 
                    curr++;
                ans = Math.max(ans, curr); 
            }
        }
        return ans;
    }
}

Complexity Analysis

  • Time Complexity: O(?)
  • Space Complexity: O(?)

Approach

Detailed explanation of the approach will be added here