3018. Make String A Subsequence Using Cyclic Increments¶
Difficulty: Medium
LeetCode Problem View on GitHub
3018. Make String a Subsequence Using Cyclic Increments
Medium
You are given two 0-indexed strings str1 and str2.
In an operation, you select a set of indices in str1, and for each index i in the set, increment str1[i] to the next character cyclically. That is 'a' becomes 'b', 'b' becomes 'c', and so on, and 'z' becomes 'a'.
Return true if it is possible to make str2 a subsequence of str1 by performing the operation at most once, and false otherwise.
Note: A subsequence of a string is a new string that is formed from the original string by deleting some (possibly none) of the characters without disturbing the relative positions of the remaining characters.
Example 1:
Input: str1 = "abc", str2 = "ad" Output: true Explanation: Select index 2 in str1. Increment str1[2] to become 'd'. Hence, str1 becomes "abd" and str2 is now a subsequence. Therefore, true is returned.
Example 2:
Input: str1 = "zc", str2 = "ad" Output: true Explanation: Select indices 0 and 1 in str1. Increment str1[0] to become 'a'. Increment str1[1] to become 'd'. Hence, str1 becomes "ad" and str2 is now a subsequence. Therefore, true is returned.
Example 3:
Input: str1 = "ab", str2 = "d" Output: false Explanation: In this example, it can be shown that it is impossible to make str2 a subsequence of str1 using the operation at most once. Therefore, false is returned.
Constraints:
1 <= str1.length <= 1051 <= str2.length <= 105str1andstr2consist of only lowercase English letters.
Solution¶
class Solution {
public boolean canMakeSubsequence(String str1, String str2) {
int m = str1.length();
int n = str2.length();
int j = 0;
for(int i = 0; i < m && j < n; i++){
int a = str1.charAt(i);
int b = str2.charAt(j);
if(a == b || a + 1 == b || a - 25 == b) j++;
}
return j == n;
}
}
Complexity Analysis¶
- Time Complexity:
O(?) - Space Complexity:
O(?)
Approach¶
Detailed explanation of the approach will be added here