2699. Count The Number Of Fair Pairs¶
Difficulty: Medium
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2699. Count the Number of Fair Pairs
Medium
Given a 0-indexed integer array nums of size n and two integers lower and upper, return the number of fair pairs.
A pair (i, j) is fair if:
0 <= i < j < n, andlower <= nums[i] + nums[j] <= upper
Example 1:
Input: nums = [0,1,7,4,4,5], lower = 3, upper = 6 Output: 6 Explanation: There are 6 fair pairs: (0,3), (0,4), (0,5), (1,3), (1,4), and (1,5).
Example 2:
Input: nums = [1,7,9,2,5], lower = 11, upper = 11 Output: 1 Explanation: There is a single fair pair: (2,3).
Constraints:
1 <= nums.length <= 105nums.length == n-109 <= nums[i] <= 109-109 <= lower <= upper <= 109
Solution¶
class Solution {
public long countFairPairs(int[] nums, int lower, int upper) {
int n = nums.length;
long count = 0;
Arrays.sort(nums);
return solve(nums, upper) - solve(nums, lower - 1);
}
private long solve(int arr[], int sum) {
int n = arr.length;
long res = 0;
int start = n - 1;
for (int i = 0; i < start; i++) {
while (i < start && arr[i] + arr[start] > sum) start--;
res += start - i;
}
return res;
}
}
Complexity Analysis¶
- Time Complexity:
O(?) - Space Complexity:
O(?)
Approach¶
Detailed explanation of the approach will be added here