1566. Check If A Word Occurs As A Prefix Of Any Word In A Sentence¶
Difficulty: Easy
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1566. Check If a Word Occurs As a Prefix of Any Word in a Sentence
Easy
Given a sentence that consists of some words separated by a single space, and a searchWord, check if searchWord is a prefix of any word in sentence.
Return the index of the word in sentence (1-indexed) where searchWord is a prefix of this word. If searchWord is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1.
A prefix of a string s is any leading contiguous substring of s.
Example 1:
Input: sentence = "i love eating burger", searchWord = "burg" Output: 4 Explanation: "burg" is prefix of "burger" which is the 4th word in the sentence.
Example 2:
Input: sentence = "this problem is an easy problem", searchWord = "pro" Output: 2 Explanation: "pro" is prefix of "problem" which is the 2nd and the 6th word in the sentence, but we return 2 as it's the minimal index.
Example 3:
Input: sentence = "i am tired", searchWord = "you" Output: -1 Explanation: "you" is not a prefix of any word in the sentence.
Constraints:
1 <= sentence.length <= 1001 <= searchWord.length <= 10sentenceconsists of lowercase English letters and spaces.searchWordconsists of lowercase English letters.
Solution¶
class Solution {
public int isPrefixOfWord(String sentence, String target) {
int n = sentence.length();
ArrayList<String> res = new ArrayList<>();
sentence += " ";
String current = "";
for (int i = 0; i < sentence.length(); i++) {
char curr = sentence.charAt(i);
if (curr == ' ') {
res.add(current);
current = "";
}
else current += curr;
}
for (int i = 0; i < res.size(); i++) {
if (res.get(i).startsWith(target)) return i + 1;
}
return -1;
}
}
Complexity Analysis¶
- Time Complexity:
O(?) - Space Complexity:
O(?)
Approach¶
Detailed explanation of the approach will be added here