104. Maximum Depth Of Binary Tree¶
Difficulty: Easy
LeetCode Problem View on GitHub
104. Maximum Depth of Binary Tree
Easy
Given the root of a binary tree, return its maximum depth.
A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1:

Input: root = [3,9,20,null,null,15,7] Output: 3
Example 2:
Input: root = [1,null,2] Output: 2
Constraints:
- The number of nodes in the tree is in the range
[0, 104]. -100 <= Node.val <= 100
Solution¶
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
static int height;
public int maxDepth(TreeNode root) {
height = 0;
dfs(root);
return height;
}
static int dfs(TreeNode root) {
if (root == null) return 0;
int left = dfs(root.left);
int right = dfs(root.right);
height = Math.max(height, Math.max(left, right) + 1);
return Math.max(left, right) + 1;
}
}
Complexity Analysis¶
- Time Complexity:
O(?) - Space Complexity:
O(?)
Approach¶
Detailed explanation of the approach will be added here